Array-wise operations

[Bob Cowdery]

 On 12/10/2010 21:11, Simen kjaeraas wrote:
> Bob Cowdery <bob at bobcowdery.plus.com> wrote:
>
>>  On 12/10/2010 20:29, Simen kjaeraas wrote:
>>> Bob Cowdery <bob at bobcowdery.plus.com> wrote:
>>>
>>>> x_points[]
>>>> =(x_average[0]+x_average[1]+x_average[2]+x_average[3]+x_average[4]+x_average[5]+
>>>>
>>>>
>>>> x_average[6]+x_average[7]+x_average[8]+x_average[9])/10;
>>>>
>>>> The average gives me a compile error of incompatible types.
>>>
>>> You need to append [] to x_average[index].
>>>
>>>
>> Thanks. I tried it the other way round [][0]. To put [0][] seems to me
>> the wrong way round. Probably just not understanding the syntax
>> properly.
>
> Yeah, it's a bit the wrong way around, for those coming from C, at least.
> The idea is that for any T[] t, t[0] should behave as if a function
> returning a T. So, for char[][] c, c[0] returns char[], which would then
> be indexed by the next brackets. If index was the function:
>
> c[0][1] => index( index( c, 0 ), 1 );
>
>
Ok, kind of understand that. Now I have another problem.

x_average[ptr] = x_points; // tells me array length don't match.

When I print x_average[ptr] or x_average[][ptr] or x_average[ptr][] they
all tell me the length is 10. What do I have to do to get to the row
which is 600?