Calling anonymous delegate recursively ?
Andrej Mitrovic
andrej.mitrovich at gmail.com
Sat Jan 8 09:40:43 PST 2011
As a workaround you can do this for now:
import std.stdio;
enum deleg = returnFib();
ulong delegate(ulong m) returnFib()
{
return (ulong m)
{
if(m < 2)
return m;
return deleg(m-1)+deleg(m-2);
};
}
void main()
{
writeln(returnFib()(10));
}
Otherwise I'd really like the ability for a lambda to call itself.
Perhaps a feature request is in order.
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