Is this a bug in iota?

[Brad Anderson]

The following code:

     import std.range;
     void main()
     {
         auto i = iota(3);
         writeln(i.front, ", length: ", i.length); i.popFront();
         writeln(i.front, ", length: ", i.length); i.popFront();
         writeln(i.front, ", length: ", i.length); i.popFront();
         writeln(i.front, ", length: ", i.length); i.popFront();
         writeln(i.front, ", length: ", i.length); i.popFront();
     }

Outputs:

     0, length: 3
     1, length: 2
     2, length: 1
     3, length: 0
     4, length: 4294967295

You can popFront() for as long as you want well passed the 
length. Obviously popping off the front of a zero length range 
isn't valid but I would have expected a range violation to occur 
rather than it to silently continuing the series with a wrapped 
around length.

I was actually looking for an infinite counting range when I 
stumbled across this. sequence() works but something even simpler 
like iota() would be better. I suspect, however, that this 
behavior was unintended.

Regards,
Brad Anderson