caller trouble

captaindet 2krnk at gmx.net
Fri Jul 13 23:53:34 PDT 2012


i need a discreet handle on the calling/instantiating source file (module). using __FILE__, it is surprisingly easy for functions (via argument) and templated functions (via template parameter) but i cannot get it working for templated classes. how can i make them aware of the calling module?

thx, det


module other;

string fun(string infile = __FILE__){ return infile; }
string tfun(string infile = __FILE__)(){ return infile; }
class tclass(string infile = __FILE__){ string from = infile; }

//...//

module main;	
import other;

void main(){
     auto _fun = fun();			//_fun == "main.d"
     auto _tfun = tfun();		//_tfun == "main.d"
     auto _tclass = new tclass!();	//_tclass.from == "other.d" !!!

     //this works but i do not want to provide __FILE__ explicitly:
     auto _tclassx = new tclass!(__FILE__)();	//_tclass.from == "main.d"
     //and why do i get 2 different results for the last 2 cases?
}


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