caller trouble
captaindet
2krnk at gmx.net
Fri Jul 13 23:53:34 PDT 2012
i need a discreet handle on the calling/instantiating source file (module). using __FILE__, it is surprisingly easy for functions (via argument) and templated functions (via template parameter) but i cannot get it working for templated classes. how can i make them aware of the calling module?
thx, det
module other;
string fun(string infile = __FILE__){ return infile; }
string tfun(string infile = __FILE__)(){ return infile; }
class tclass(string infile = __FILE__){ string from = infile; }
//...//
module main;
import other;
void main(){
auto _fun = fun(); //_fun == "main.d"
auto _tfun = tfun(); //_tfun == "main.d"
auto _tclass = new tclass!(); //_tclass.from == "other.d" !!!
//this works but i do not want to provide __FILE__ explicitly:
auto _tclassx = new tclass!(__FILE__)(); //_tclass.from == "main.d"
//and why do i get 2 different results for the last 2 cases?
}
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