Initializing multidimentional Array with a struct

[Chris Pons]

Yes sorry, I was looking to initialize to the default value of 
node. Thank you for the help!

On Saturday, 31 March 2012 at 21:59:50 UTC, Ali Çehreli wrote:
> On 03/31/2012 02:34 PM, Chris Pons wrote:
> > I'm trying to figure out how to initialize a
> multi-dimentional array
> > with a struct. I thought it would be straight forward, but
> i'm running
> > into problems. I'm using nested for loops, and just setting
> the current
> > index to a blank version of my struct but that gives me this
> error:
> > "Error: no [] operator overload for type Node". I didn't know
> I needed
> > to overload that operator, usually didn't need to in C++ as
> far as I
> > remember.
> >
> > struct Node
> > {
> > bool walkable;
> > vect2 position;
> > int xIndex, yIndex;
> > Node*[4] connections;
> > }
> >
> > void InitializePathGraph()
> > {
> > for( int x = 0; x < mapWidth; x++ )
> > {
> > for( int y = 0; y < mapHeight; y++ )
> > {
> > Node node;
> > PathGraph[x][y] = node;// ERROR
> > }
> > }
> > }
> >
> >
>
> Do you want to initialize with the default value of Node? Then 
> it is as easy as the following:
>
> import std.stdio;
>
> struct Node
> {}
>
> void main()
> {
>     Node[2][3] a;       // fixed-length of fixed-length
>     Node[][] b = new Node[][](2, 3);  // slice of slice
>
>     writeln(a);
>     writeln(b);
> }
>
> The output:
>
> [[Node(), Node()], [Node(), Node()], [Node(), Node()]]
> [[Node(), Node(), Node()], [Node(), Node(), Node()]]
>
> Please note the different meanings of 2 and 3 for the 
> fixed-length array and the new expression: lines and rows are 
> swapped!
>
> Ali