Method-call based on template argument
sclytrack
sclytrack at iq87.fr
Wed May 9 04:12:27 PDT 2012
On 05/09/2012 12:33 PM, nrgyzer wrote:
> void main() {
>
> int a = 10;
> int b = 20;
> std.stdio.writeln(calculate!("add")(a, b));
> std.stdio.writeln(calculate!("subtract")(a, b));
>
> }
Below works
-----------
import std.stdio;
int calculate(string T)(int a, int b) if(T == "add")
{
return a + b;
}
int calculate(string T)(int a, int b) if(T == "subtract")
{
return a - b;
}
void main() {
int a = 10;
int b = 20;
std.stdio.writeln(calculate!("add")(a, b));
std.stdio.writeln(calculate!("subtract")(a, b));
}
Output
------
30
-10
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