floating point divide

[bearophile]

Damian:

> I come from a pascal background and we could use:
> div    integral division operator
> /      floating point division operator

Two operators for the two different operations is a design better
than C, that is bug-prone.


> So my question is, how does D force floating point division on 
> integrals?
> At the moment i do this, but i was hoping for an easier way:
>
> int n1 = 10, n2 = 2;
> float f = cast(float)(cast(float)(n1 / n2));

That's not good, it performs an integer division, followed by two
float casts.

Note: float is useful only if you have many of them, or if you
pass/return pairs of them. A single float is not so useful.

A solution:

int n1 = 10, n2 = 2;
const f = n1 / cast(double)n2;

Using type inference is useful, as it doesn't hide an integer
result if your code is wrong.

Bye,
bearophile