Can i rewrite methods in one line?

[Ali Çehreli]

On 09/02/2012 07:57 PM, Ivan Agafonov wrote:

 > ref Vector opOpAssign(string op) (T rhs) if(op == "+" || op == "-" || op
 > == "*" || op == "/")
 > { mixin("array[] "~op~"= rhs;"); return this; }
 >
 > But i can't write something like this:
 > return Vector(mixin("array[] "~op~"= rhs.array[]"));

You meant it for opOpAssign, right?

opOpAssign must 'return this', not a new object. Otherwise chaining 
operators would be confusing:

     (v0 += v1) *= v2;

If the += operation could return a new object (which it can't), then *= 
would be operating on that.

So your existing version is correct:

     ref Vector opOpAssign(string op) (T[size] rhs)
         if(op == "+" || op == "-" || op == "*" || op == "/")
     { mixin("array[] "~op~"= rhs[];"); return this; }

But if you don't care about chained operations you can also return void:

     void opOpAssign(string op) (T[size] rhs)
         if(op == "+" || op == "-" || op == "*" || op == "/")
     { mixin("array[] "~op~"= rhs[];"); }

Ali