auto limitation?
Ali Çehreli
acehreli at yahoo.com
Tue Sep 11 11:33:14 PDT 2012
On 09/11/2012 11:10 AM, Namespace wrote:
> I have this code, but it works not as expected:
> http://dpaste.dzfl.pl/6ce5b4dd
>
> I get 0 instead of 42 if my type is Int.
> My value is correct (as you can see) but "writeln" prints still 0
> instead of 42.
> I think "auto" compiles first to float and cannot handle then integers.
> Am I right? And could you explain me how this could work?
Here is a reduced code:
import std.stdio;
enum Type { Int, Float }
auto foo(Type t)
{
final switch (t) {
case Type.Int:
return 42;
case Type.Float:
return 1.5;
}
}
void main()
{
writeln(foo(Type.Int));
writeln(foo(Type.Float));
}
The return type of foo() is double. (It's float in your code but it
doesn't matter.)
I think this is a bug. I guess that 'return 42' is still placing an int
onto the program stack instead of a float. A workarounds are returning
to!float(this._num.ivalue).
But I think this is a compiler bug.
Ali
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