access enclosing type from shared static this()
Timon Gehr
timon.gehr at gmx.ch
Wed Sep 19 12:52:35 PDT 2012
On 09/19/2012 09:37 PM, "Øivind" wrote:
> I want to access the type of the enclosing struct in in a shared static
> initializer.. How do I do that? The following code will not compile:
>
> mixin template MsgMixin(T ...) {
> static string getName(this M)() {
> return M.stringof;
> }
> shared static this() {
> import std.stdio;
> writeln("register " ~ getName());
> }
> }
>
> struct MsgTestMsg {
> mixin MsgMixin!();
> }
>
> I get the following error messages:
>
> src/main.d(40): Error: template main.MsgTestMsg.MsgMixin!().getName does
> not match any function template declaration
> src/main.d(40): Error: template main.MsgTestMsg.MsgMixin!().getName(this
> M) cannot deduce template function from argument types !()()
>
> If not possible, just getting the name of the enclosing struct would
> help a lot!
>
> -Øivind
>
use typeof(this), eg:
mixin template MsgMixin(T ...) {
shared static this() {
import std.stdio;
writeln("register " ~ typeof(this).stringof);
}
}
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