Any trick for defining an operator overload in a different namespace?

[Ali Çehreli]

On 08/31/2013 03:07 AM, Andrej Mitrovic wrote:

 > I'm trying to achieve the syntax "opts[...] = 123", rather than using
 > the more direct "this[...] = 123". I can use this code:
 >
 > -----
 > class C
 > {
 >      this()
 >      {
 >          opts = Opts(this);
 >          opts["foo"] = 1;
 >      }
 >
 >      struct Opts
 >      {
 >          C c;
 >
 >          void opIndexAssign(T)(T value, string option)
 >          {
 >              c.assign(option, value);
 >          }
 >      }
 >
 >      Opts opts;
 >
 >      private void assign(string option, int value)
 >      {
 >      }
 > }
 >
 > void main()
 > {
 >      auto c = new C();
 > }
 > -----
 >
 > But this explicitly stores the 'this' reference in the struct, I was
 > wondering if anyone knows of a trick to avoid having to do that. As
 > you can tell I just want a more convenient operator-based syntax over
 > calling the 'assign' method, but I don't want the operator to live in
 > the class space itself (because then I'd have to use "this[...] =
 > that", which is a little quirky for my taste).
 >

This is the limitation of inner structs' not having an 'outer' 
reference, right?

Even if that were automatically available, it would still need a 
reference similar to your explicit 'c' reference. I think... :)

Ali