ubytes to ulong problem
ponce
contact at g3mesfrommars.fr
Sat Dec 21 14:31:03 PST 2013
On Saturday, 21 December 2013 at 22:29:59 UTC, ponce wrote:
> On Saturday, 21 December 2013 at 22:22:09 UTC, Charles Hixson
> wrote:
>> I was planning to ask if there were a better way to do this,
>> but instead I need to ask what's my mistake?
>> For some reason, if called with an uninitialized ubyte array,
>> and an index of 0, it returns a value of 8, even though all
>> the values in the array are 0.
>> The error has to be somewhere in the "ret = " statement, but I
>> sure don't see it.
>>
>> /** Convert 8 consecutive bytes sliced from a ubyte[] into
>> a ulong
>> * @param block The array from which to slice.
>> * @param n The starting index within the block */
>> ulong ubytesToUlong(ubyte[] block, int n)
>> { ulong ret;
>> assert (n >= 0);
>> assert (n + 8 <= block.length);
>> writefln ("n = %s", n);
>> writefln ("block[0] = %s", cast(ulong)block[0]);
>> writefln ("block[1] = %s", cast(ulong)block[1]);
>> writefln ("block[2] = %s", cast(ulong)block[2]);
>> writefln ("block[3] = %s", cast(ulong)block[3]);
>> writefln ("block[4] = %s", cast(ulong)block[4]);
>> writefln ("block[5] = %s", cast(ulong)block[5]);
>> writefln ("block[6] = %s", cast(ulong)block[6]);
>> writefln ("block[7] = %s", cast(ulong)block[7]);
>> ret = cast(ulong)block[n] * 2^21
>> + cast(ulong)block[n+1] * 2^18
>> + cast(ulong)block[n+2] * 2^15
>> + cast(ulong)block[n+3] * 2^12
>> + cast(ulong)block[n+4] * 2^9
>> + cast(ulong)block[n+5] * 2^6
>> + cast(ulong)block[n+6] * 2^3
>> + cast(ulong)block[n+7] * 2^0;
>> writefln ("ret = %s", ret);
>> return ret;
>> }
Use the exponentiation operator which is spelled: ^^
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