Task to throw away string parts, use joiner and splitter not very successful
bearophile
bearophileHUGS at lycos.com
Tue Dec 31 16:19:36 PST 2013
Chris Cain:
> From your error message: isForwardRange!Separator
>
> Your separator is a character, which isn't a forward range. Try
> this:
> `auto name1 = joiner(nameparts[0 .. $-1], ".");`
But splitting on a char is a common operation, and isn't it more
efficient than splitting on a string?
Bye,
bearophile
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