make a nothrow call a throwing function

[1100110]

On 02/07/2013 05:38 AM, monarch_dodra wrote:
> On Thursday, 7 February 2013 at 10:55:26 UTC, Jonathan M Davis wrote:
>> On Thursday, February 07, 2013 11:06:14 monarch_dodra wrote:
>>> Is there any way that a nothrow function can call a function that
>>> throws, but without even trying to catch if an exception is
>>> thrown?
>>>
>>> My use case is a pretty low level nothrow function, that needs to
>>> call something that never ever throws, but was not marked as such.
>>>
>>> I want to avoid the "try/catch/[do nothing|assert]" because I
>>> don't want to pay for that. Ideally, i'd really just want to mark
>>> my function as nothrow, and have undefined behavior if it *does*
>>> throw.
>>>
>>> Any way to do that?
>>
>> You can cast the function.
>>
>> - Jonathan M Davis
>
> Smart.
>
> Unfortunatly, in this case, I'm trying to call "string.dup".
>
> It would appear though that (apparently), dup is a property that returns
> a function pointer, or something. In any case, I can't seem to be able
> to get its address.
>
> Now I feel kind of bad for suggesting banning taking the address of a
> property function ...
>
> I can bypass this with a wrapper function I guess, but at this point,
> I'd have to bench to see if that is even worth it...

scope(failure) has worked for me in the past, but mostly calling C 
functions from nothrow.

You do have to put it at the top of the function, but it's simple and nice.