Declare reference to variable ?

[Namespace]

On Monday, 29 July 2013 at 21:25:21 UTC, Temtaime wrote:
> No, i cannot.
>
> struct S {
> 	uint longnamed;
> }
>
> void main() {
> 	S somestruct;
>
> 	alias v = somestruct.longnamed;
> 	writeln(v);
> }
>
> Error: need 'this' for 'longnamed' of type 'uint'
>
> Is it a bug ?

Oh, that is annoying...
Then, make your own reference type:

import std.stdio;

struct S {
	uint longnamed;
}

struct Ref(T) {
public:
	T* ptr;
	
	@disable
	this();
	
	/*@disable
	this(this);*/
	
	@disable
	this(typeof(null));
	
	@disable
	void opAssign(ref Ref!T);
	
	this(T* ptr) {
		this.ptr = ptr;
	}
	
	@property
	ref inout(T) get() inout {
		return *this.ptr;
	}
	
	alias get this;
}

void main() {
	S somestruct;

	Ref!uint v = &somestruct.longnamed;
	writeln(v);
}