randomShuffle

[bearophile]

Yann:

> Is there a better way to accomplish this? Naively, I would 
> expect something like
> "return iota(1, 1000).randomShuffle.take(10).sort;"

Two ways, the first gives items in random order, the second 
ordered as you seem to desire:

import std.stdio, std.random, std.range, std.array;
void main() {
     iota(1, 1001).randomCover(rndGen).take(10).writeln;
     iota(1, 1001).randomSample(10).writeln;
}


But be careful with randomCover, because maybe it takes the rnd 
generator by value.

Bye,
bearophile