How to expand an expression along with a parameter tuple?

[Artur Skawina]

On 06/17/13 11:32, TommiT wrote:
> On Monday, 17 June 2013 at 07:20:23 UTC, Ali Çehreli wrote:
>>
>> The following does not answer the question of expanding but at least foo() receives [30, 70, 110] :)
>>
>> import std.stdio;
>> import std.algorithm;
>> import std.array;
>> import std.range;
>>
>> int[] arr = [ 1, 3, 5, 7, 11 ];
>>
>> void foo(T)(T[] values...)
>> {
>>     writeln(values);
>> }
>>
>> void bar(T)(T[] values...)
>> {
>>     foo(arr
>>         .indexed(values)
>>         .map!(a => a * 10)
>>         .array);
>> }
>>
>> void main()
>> {
>>     bar(1, 3, 4);
>> }
>>
>> Ali
> 
> Yeah, that would work. I'd hate the overhead though.

   void bar(T...)(T values) {
      T tmp;
      foreach (i, ref v; values)
         tmp[i] = arr[v]*10;
      foo(tmp);
   }

artur