Possible bug

[Sergei Nosov]

On Tuesday, 26 March 2013 at 05:40:00 UTC, Steven Schveighoffer 
wrote:
> What you have to do is instantiate the template, then call the 
> constructor:
>
> S!(int, 4).S!(byte, 5)(3)
>
> Note that the way templates work in D, a templated struct is 
> really a shortcut for:
>
> template S(T)
> {
>    struct S { ... }
> }
>
> So when you instantiate it, S!(int)(5) is really shorthand for 
> S!(int).S(5).
>
> Every template is this way.  The shorthand version calls on the 
> "eponymous" member implicitly, that is, the member with the 
> same name as the template.  Currently, this only works if there 
> is exactly one member.
>
> For example, a function template is really:
>
> template foo(T)
> {
>    void foo(T t) {...}
> }
>
> So doing:
>
> foo!(int)(1)
>
> is really the same as:
>
> foo!(int).foo(1)
>
> It's all outlined here: http://dlang.org/template.html
>
> search for Implicit Template Properties
>
> -Steve

Thx a lot!