how use lowerBound with just sorting key, not complete values
Daniel Davidson
nospam at spam.com
Tue Nov 12 08:46:10 PST 2013
On Tuesday, 12 November 2013 at 16:34:30 UTC, bearophile wrote:
> Daniel Davidson:
>
>> Yes, but that is only giving the dates. I want the actual
>> array elements. Suppose S is a large object with lots of extra
>> fields in addition to `string foo`. There should be a way to
>> pull out the lower bound based on a date without creating a
>> needle (S). Maybe lowerBound is not the right function?
>
> Second try:
>
> import std.stdio, std.range, std.datetime, std.algorithm,
> std.array, std.typecons;
>
> struct S {
> Date date;
> string foo;
> }
>
> void main() {
> auto sarr = [S(Date(2000, 1, 1), "x"),
> S(Date(2000, 2, 1), "a"),
> S(Date(2000, 3, 1), "foo")];
> assert(sarr.isSorted!q{ a.date < b.date });
>
> sarr.writeln;
> auto needle = S(Date(2000, 2, 1));
>
> sarr
> .map!(s => s.date)
> .zip(sarr.length.iota)
> .assumeSorted!q{ a[0] < b[0] }
> .lowerBound(tuple(needle.date, 0))
> .map!(p => sarr[p[1]])
> .writeln;
> }
>
>
> Output:
>
> [S(2000-Jan-01, "x"), S(2000-Feb-01, "a"), S(2000-Mar-01,
> "foo")]
> [S(2000-Jan-01, "x")]
>
> Bye,
> bearophile
Well, I think that is it. Thanks, bearophile!
Pardon the redirect, but while you are at it, I would appreciate
your take on this one
(http://forum.dlang.org/post/gofijmqwhfcwgbruzkvz@forum.dlang.org).
I'm sure you'll improve it and teach me a few things on the way
;-)
Thanks
Dan
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