Accessing a Hash table as a Value-Sorted Range
Ali Çehreli
acehreli at yahoo.com
Tue Nov 19 14:48:01 PST 2013
On 11/19/2013 02:42 PM, "Nordlöw" wrote:
> On Tuesday, 19 November 2013 at 21:14:01 UTC, Brad Anderson wrote:
>> On Tuesday, 19 November 2013 at 21:11:42 UTC, Nordlöw wrote:
>>> If I have a hash-table `File[string] _subs` and want to access its
>>> values in a sorted way is there a better than simply through
>>>
>>>
>>> auto ssubs = new File[_subs.length]; // preallocate sorted subs
>>> size_t ix = 0;
>>> foreach (sub; _subs) {
>>> ssubs[ix++] = sub; // set new reference to sub
>>> }
>>>
>>> ssubs.sort!((a, b) => (a.timeLastModified >
>>> b.timeLastModified));
>>>
>>> return ssubs;
>
> I just found that I can use the .values property member:
>
> import std.stdio, std.algorithm;
> string[int] x = [0:"b", 1:"a"];
> auto y = x.values.map!("a~a");
> writeln(y);
There is also the lazy range .byValue:
x.byValue
.values returns an array. It is kind of the equivalent of the following:
import std.array;
// ...
x.byValue.array
Ali
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