LPOLESTR* to string

[Andre]

Am 10.02.2014 18:54, schrieb John Colvin:
> On Monday, 10 February 2014 at 17:29:33 UTC, John Colvin wrote:
>> On Monday, 10 February 2014 at 17:08:27 UTC, Andre wrote:
>>> Am 10.02.2014 17:53, schrieb Mike Parker:
>>>> On 2/11/2014 1:32 AM, Andre wrote:
>>>>> Hi,
>>>>>
>>>>> one hour trying to get a string out of LPOLESTR*.
>>>>> What is the correct command to get rgszNames as string?
>>>>>
>>>>> HRESULT GetIDsOfNames(REFIID riid, LPOLESTR* rgszNames, UINT cNames,
>>>>> LCID lcid, DISPID* rgDispId){}
>>>>>
>>>>> With following command I only get the first character
>>>>> writeln(to!string(**rgszNames));
>>>>>
>>>>> Kind regards
>>>>> André
>>>>
>>>> I would assume to!string(*rgszNames). Assuming LPOLESTR is char* or
>>>> some
>>>> such, then LPOLESTR** is char**, so **LPOLESTR would be the first
>>>> character in the string, and *LPOLESTR would be the char* string.
>>>
>>>
>>> to!string(*rgszNames) outputs a number instead of a name.
>>> I think I am a step further, rgszNames is an array but also with
>>> to!string(*rgszNames[0]) only the first character of my method is
>>> given back.
>>>
>>> Kind regards
>>> André
>>
>> std.conv.to knows about char* c-style strings, but not wchar* c-style
>> strings like LPOLESTR. The number you are getting is the pointer to
>> the first wchar.
>>
>> I'm not sure what is the best way to do this as it's not something
>> I've come across before, hopefully someone else will know.
>
> I'm pretty sure you can get a wstring like this:
>
> import core.stdc.wchar_ : wcslen;
> auto rgszNamesWStr = to!wstring(rgszNames[0][0 .. wcslen(rgszNames[0])]);
>
> Or if you're sure you don't have any wide characters:
>
> auto rgszNamesStr = to!string(rgszNames[0][0 .. wcslen(rgszNames[0])]);


Yes:) now it works.
Thanks a lot.

Kind regards
André