I'd say
import std.algorithm;
auto cross(R1,R2)(R1 a, R2 b) {
	return cartesianProduct(a,b).map!"[a[0]]~[a[1]]"();
}
You can always:
import std.array;
auto strings = array(cross("ab","12"));
Although that won't give you a string[], but in a dchar[][].