Function to print a diamond shape

[monarch_dodra]

On Thursday, 20 March 2014 at 21:25:03 UTC, Ali Çehreli wrote:
> What interesting, boring, efficient, slow, etc. ways are there?
>
> Ali

I'd be interested in seeing a solution using "iota", and the 
currently proposed "each" or "tee". A quick protype to draw a 
triangle would be:

iota(0, n).each!(a=>q{%(*%)}.writefln(a.iota()))();
or
iota(0, n).each!(a=>'*'.repeat(a).writeln())();

Adapting that to do a diamond should be straight forward? It 
would be a good benchmark of functional vs imperative code, and 
the usability of "each".