std.utf.decode("dlang", 1)
Ali Çehreli via Digitalmars-d-learn
digitalmars-d-learn at puremagic.com
Wed Sep 17 23:26:07 PDT 2014
On 09/17/2014 11:23 PM, Algo wrote:
> On Thursday, 18 September 2014 at 06:09:54 UTC, Algo wrote:
>> void main()
>> {
>> import std.utf;
>> decode("dlang", 1);
>> }
>>
>> Error: template std.utf.decode cannot deduce function from
>> argument types !()(string, int), candidates are:
>> D:\msc\D\dmd2\windows\bin\..\..\src\phobos\std\utf.d(924):
>> std.utf.decode(S)(auto ref S str, ref size_t index) if
>> (!isSomeString!S && isRandomAccessRange!S && hasSlicing!S &&
>> hasLength!S && isSomeChar!(ElementType!S))
>> D:\msc\D\dmd2\windows\bin\..\..\src\phobos\std\utf.d(942):
>> std.utf.decode(S)(auto ref S str, ref size_t index) if
>> (isSomeString!S)
>>
>> why doesn't "decode(S)(auto ref S str, ref size_t index) if
>> (isSomeString!S)" correspond?
>
> rvalues cannot be ref it seems
Yes. Interestingly, in D rvalues cannot be bound even to const ref.
void main()
{
import std.stdio;
import std.utf;
size_t index = 1;
dchar decoded = decode("dlang", index);
writefln("decoded '%s', next character is at index %s.",
decoded, index);
}
The output:
decoded 'l', next character is at index 2.
Ali
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