expand variadic template parameters

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On Tuesday, 10 March 2015 at 19:11:22 UTC, André wrote:
> Hi,
>
> in this minified example I try to expand the variadic parmaters 
> of
> foo to bar:
>
> import std.typecons;
>
> void foo(T ...)(T args)
> {
>      bar(args.expand);
> }
>
> void bar(int i, string s){}
>
> void main()
> {
> 	foo(1, "a");
> }
>
> I got the syntax error: no property 'expand' for type '(int,
> string)'
> I understand args is a TypeTuple and therefore expand is not
> working.
> Is there a simple way to get it working?
>
> Kind regards
> André

Just to be clear, TypeTuple is a library construct defined in 
std.typetuple. It doesn't have a .expand member as far as I know. 
You're probably thinking of tuple.expand.

The type of `T ...` is not TypeTuple, but an internal tuple type 
used by the compiler. TypeTuple is just some syntactic sugar 
allowing you to create one of these compiler tuples.