parallel

[anonymous via Digitalmars-d-learn]

On 05.11.2015 21:30, Handyman wrote:
> Seems that 4 cores go all out on first 4 dishes, then 1 core deals with
> the last dish.  With 4 cores I expect diner is ready after 5/4 = 1.25
> secs though.  What did I do wrong?

You describe the situation correctly. The unit of work is a dish. That 
is, the work for a single dish is not split between cores. So one of 
your four cores has to make two dishes. That takes two seconds.