chaining chain Result and underlying object of chain

[Steven Schveighoffer via Digitalmars-d-learn]

On 9/14/15 11:30 AM, Ali Çehreli wrote:
> On 09/14/2015 08:01 AM, Laeeth Isharc wrote:
>  > I was trying to use the same variable eg
>  >
>  >        auto chain1 = chain("foo", "bar");
>  >        chain1 = chain(chain1, "baz");
> [...]
>  > It may be that the type of chain1
>  > and chain2 don't mix.
>
> Exactly.
>
> I was going to recommend using pragma(msg, typeof(chain1)) to see what
> they are but it looks like chain()'s return type is not templatized. (?)
>
>      pragma(msg, typeof(chain1));
>      pragma(msg, typeof(chain2));
>
> Prints
>
> Result
> Result
>
> instead of something like (hypothetical)
>
> ChainResult!(string, string)
> ChainResult!(ChainResult!(string, string), string)
>
> Ali
>
typeid is a bit better:

import std.range;

void main()
{
     import std.stdio;
     auto chain1 = chain("hi", "there");
     auto chain2 = chain(chain1, "friend");
     writeln(typeid(chain1));
     writeln(typeid(chain2));
}

output:

std.range.chain!(string, string).chain.Result
std.range.chain!(Result, string).chain.Result

I still see that "Result" as a parameter for chain2.

I think the compiler should be better at printing these types at compile 
time.

-Steve