simple range question
Edwin van Leeuwen via Digitalmars-d-learn
digitalmars-d-learn at puremagic.com
Fri Apr 8 13:21:51 PDT 2016
On Friday, 8 April 2016 at 18:27:59 UTC, Laeeth Isharc wrote:
> suppose I have a forward or random access range. what's the
> best way to compare each element with the element 4 elements
> prior to that element? I could map each element to a tuple of
> the element and the element 4 bars previously and do it that
> way. any neater way ?
I'd do it like this, but I guess that is what you mean with
mapping it to a tuple:
zip( r, r[4..$] ).map!((t) => t[0] == t[1]);
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