Get size of mem to free by free

[H.Loom via Digitalmars-d-learn]

On Friday, 5 August 2016 at 20:54:59 UTC, Mark "J" Twain wrote:
> On Friday, 5 August 2016 at 20:43:12 UTC, H.Loom wrote:
>> On Friday, 5 August 2016 at 19:55:22 UTC, Mark "J" Twain wrote:
>>> [...]
>>
>> You can wrap the C memory allocations functions with a version 
>> identifier, e.g
>>
>>
>> version(stat)
>> {
>>     __gshared size_t[size_t] sizes;
>> }
>>
>> version(stat)
>> {
>>     auto malloc(size_t size)
>>     {
>>         auto result = std.c.stdlib.malloc(size);
>>         sizes[result] = size;
>>         return result;
>>     }
>> }
>> else alias malloc = std.c.stdlib.malloc;
>>
>> version(stat)
>> {
>>     void free(void* ptr)
>>     {
>>         std.c.stdlib.free(ptr);
>>         sizes.remove(ptr);
>>     }
>> }
>> else alias free = std.c.stdlib.free;
>>
>>
>> that a bit a DIY but this would work.
>
> Yeah, I ended up just storing the sizes in the ptr on malloc. 
> Essentially the same but I don't have to keep a global around 
> and deal with that.

you cannot get rid of a global variable to store the sizes. Even 
if it's hidden in an API you didn't write, in which case it's 
just hidden.

Have you looked at experimental allocators ?