pow exponent type issue

[ag0aep6g via Digitalmars-d-learn]

On Wednesday, 24 August 2016 at 19:16:56 UTC, jmh530 wrote:
> I'm a little confused on why pow behaves so differently when 
> switching from an int to a uint for the exponent.
>
> import std.math : pow;
> import std.stdio : writeln;
>
> void main()
> {
>
> 	float x = 2;
> 	int y1 = 1;
> 	uint y2 = 1;
>
> 	writeln(pow(x, -y1));  //prints 0.5
> 	writeln(pow(x, -y2));  //prints inf
>
> }

-y1 is -1. But -y2 is uint.max, i.e. a pretty large positive 
number.

The 'u' in "uint" stands for "unsigned". That is, it doesn't know 
negative numbers. Dont' use uint when you need negative numbers.