Modify Function Pointer to Take Additional Parameters

[jmh530 via Digitalmars-d-learn]

On Friday, 19 February 2016 at 15:00:51 UTC, jmh530 wrote:
>
> This works.
>
> But when I re-write foo to take that into account as in below, 
> I get an error that I can't implicitly convert int function(int 
> x) to int function(int x, int y).


I don't think I had looked at what you had done carefully enough. 
Basically, you just define a new function and take a function 
pointer of that. That might be a brute force solution.

I tried to use a cast (below) to modify the function pointer, but 
it is printing the second number instead of the first. I find 
this behavior strange...

int foo(int x)
{
	return x;
}

void main()
{
	import std.stdio : writeln;

	auto foo_ = cast(int function(int x, int y)) &foo;
	
	writeln(foo_(1, 200)); //prints 200
}