How to declare an alias to a function literal type

[Marc Schütz via Digitalmars-d-learn]

On Tuesday, 12 January 2016 at 16:55:48 UTC, ParticlePeter wrote:
> I can rewrite the definition of otherFunc like this:
> void otherFunc( MF mf );
>
> But I cannot pass an anonymous function to otherFunc like this:
> otherFunc( MF { myCode; } );
>
> Thats what I want. Any working example?

If I understand you correctly (not sure), you would like to write 
`MF` so that you don't need to specify the parameters in the 
lambda? That's not possible, because the code inside the lambda 
needs names for them if it wants to access them, but parameter 
names are _not_ part of the function type, and therefore the 
alias doesn't know about them.

However, you don't need to specify the full parameter list in the 
lambda, the names and `ref` are enough:

     otherFunc( (ref a, ref b, ref c) { /* use a, b, c */ } );