Declaring rvalue function arguments

[Matt Elkins via Digitalmars-d-learn]

On Sunday, 31 January 2016 at 17:55:53 UTC, Matt Elkins wrote:
> Errr, ignore the makeFoo() line. Left that in by accident, has 
> no bearing on the issue.

Ok, I think I understand why this doesn't work, at least. The Foo 
passed into bar() is, of course, an lvalue itself.

So I can achieve this with a new bar(), like so:

[code]
void bar(Foo foo)
{
     import std.algorithm.mutation;
     Foo foo1 = move(foo);
}
[/code]