inout and templates don't mix...

[Ali Çehreli via Digitalmars-d-learn]

On 03/23/2016 02:31 PM, cy wrote:

 > struct Someop(Type) {
 >    Type thing;
 >    void foo() {
 >      thing.bar();
 >    }
 > }
 >
 > struct Foo {
 >    void bar() {
 >      import std.stdio: writeln;
 >      writeln("bar");
 >    }
 > }
 >
 > struct Bar {
 >    void thingy(inout(Foo) foo) inout {
 >      auto op = Someop(foo);

The following is a workaround for this example:

       auto op = Someop!Foo(foo);

I'm not sure whether Someop's implicit constructor should take part in 
deducing Someop's Type template parameter.

Ali