spawnProcess: Exit parent process without terminating child process
    timvol via Digitalmars-d-learn 
    digitalmars-d-learn at puremagic.com
       
    Fri Aug 25 12:55:09 PDT 2017
    
    
  
Hi guys,
I want execute a process. I know, I can execute a process using 
"spawnProcess" or "executeShell". But I want exit the parent.
My code for testing purposes is the following:
int main(string[] asArgs_p)
{
     if ( (asArgs_p.length >= 2) && asArgs_p[1].isDir() )
     {
         while(1) {}
     }
     else
     {
         import std.process;
         spawnProcess([asArgs_p[0], "test"]);
     }
     return 0;
}
So, starting the application without any parameter, it calls 
"spawnProcess" with an parameter. Now, I want that the parent 
process (the process started without parameter) terminates, while 
the created process remains running.
At the moment, the parent process creates the child and remains 
open (because of the while(1)-loop).
Any ideas how I can exit the parent and keep the child process 
running?
    
    
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