Sort in return statement

[Seb]

On Saturday, 9 December 2017 at 02:45:35 UTC, rjframe wrote:
> On Sat, 09 Dec 2017 02:34:29 +0000, codephantom wrote:
>
>> Anyone got ideas on how to get sort() working in the *return*
>> statement?
>> 
>> //------------
>> 
>> ushort[] draw8Numbers()
>> {
>>      import std.meta : aliasSeqOf;
>>      import std.range : iota;
>>      ushort[] numbers = [ aliasSeqOf!(iota(1,46)) ];
>> 
>>      import std.random : randomShuffle;
>>      randomShuffle(numbers);
>> 
>>      import std.range : take;
>>      import std.algorithm.sorting : sort;
>>      return numbers.take(8); /* ok */
>>      //return sort(numbers.take(8)); /* I want this, but it 
>> won't
>> work. */
>> 
>> }
>> 
>> // -------------
>
>
> `sort` returns a SortedRange of ushorts, not an array of 
> ushorts. Make it:
>
> ```
> import std.array : array;
> return sort(numbers.take(8)).array;
> ```
>
> --Ryan


Use .release to obtain the underlying array. No need to do 
another allocation!

```
numbers.take(8).sort.release;
```