[OT] Converting booleans to numbers

[Steven Schveighoffer]

On 9/21/17 3:24 PM, Timon Gehr wrote:

> This is a good alternative, maybe arrange it like this:
> 
> dfs(a + 1, b); dfs(a, b + 1);
> dfs(a - 1, b); dfs(a, b - 1);

Yes, better!

> Just need to make sure no code is duplicated. (For example, there could 
> be more work to do in each loop iteration, and then you'd need to use a 
> local function.)

Hm... I suppose you would do that work at the beginning of dfs, like you 
check the limits?

-Steve