splitter string/char different behavior
Jon Degenhardt
jond at noreply.com
Sat Sep 30 19:40:01 UTC 2017
On Saturday, 30 September 2017 at 19:26:14 UTC, SrMordred wrote:
>>> For "a.b.c"splitter(x), Range r is a string, r.front is a
>>> char. The template can only be instantiated if the predicate
>>> function is valid. The predicate function is "a == b". Since
>>> r.front is a char, then s must be a type that can be compared
>>> with '=='. A string and char cannot be compared with '==',
>>> which is why the a valid template instantiation could not be
>>> found.
>>
>> Would it be correct to just update the documentation to say
>> "Lazily splits a range using an char as a separator" ? what
>> is it; wchar and dchar too?
>>
>> I notice the example that is there has ' ' as the element.
>
> But this works:
> writeln("a.b.c".splitter(".") );
Geez, my mistake. I'm sorry about that. It's dropback that's
failing, not splitter.
More information about the Digitalmars-d-learn
mailing list