Optional parameters?
Steven Schveighoffer
schveiguy at yahoo.com
Sun Apr 1 15:54:16 UTC 2018
I currently have a situation where I want to have a function that
accepts a parameter optionally.
I thought maybe Nullable!int might work:
void foo(Nullable!int) {}
void main()
{
foo(1); // error
int x;
foo(x); // error
}
Apparently, I have to manually wrap an int to get it to pass. In other
languages that support optional types, I can do such things, and it
works without issues.
I know I can do things like this:
void foo(int x) { return foo(nullable(x)); }
But I'd rather avoid such things if possible. Is there a way around
this? Seems rather limiting that I can do:
Nullable!int x = 1;
but I can't implicitly convert 1 to a Nullable!int for function calls.
-Steve
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