variable _param_0 cannot be read at compile time
learnfirst1
learnfirst1 at gmail.com
Thu Aug 9 02:55:38 UTC 2018
On Wednesday, 8 August 2018 at 13:13:42 UTC, Simen Kjærås wrote:
> On Wednesday, 8 August 2018 at 12:57:43 UTC, learnfirst1 wrote:
>> Why this is a error ?
>>
>> ```
>> struct S {
>> bool v;
>> string x;
>> }
>>
>> S* add(A...)(ref A a) {
>> __gshared s = S(a);
>> return &s;
>> }
>>
>> void main(){
>> auto p = add(true);
>> }
>> ```
>>
>> test.d(9): Error: variable _param_0 cannot be read at compile
>> time
>
> __gshared and static need to be initialized with a value known
> at compile-time. You're trying to give it a run-time value. You
> can set this after it's first created:
>
> S* add(A...)(ref A a) {
> __gshared S s;
> s = S(a);
> return &s;
> }
>
> That's a little kludgy, but apparently that's how it be.
>
> You also get another error message:
>> Error: function test.add!bool.add(ref bool _param_0) is not
>> callable using argument types (bool)
>
> That's because add takes its arguments by ref, and true is a
> literal that has no canonical address, and thus can't be passed
> by ref. You might consider using auto ref.
>
> --
> Simen
is there a way to pass A a... as alias into template ? so the
code can be just like this:
__gshared S s = S(&m, false);
the binary size is short since in this case the s is static build
int. and run a bit fast.
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