each & opApply
Alex
sascha.orlov at gmail.com
Wed May 23 13:59:30 UTC 2018
On Wednesday, 23 May 2018 at 13:49:45 UTC, Steven Schveighoffer
wrote:
>
> Right, but not foreach(el1, el2; c), which is the equivalent of
> your each call.
>
Yes. I tried this in the first place and get a compiler error.
But it seemed logical to me, that if I define two opApply
overloads, which both matches two arguments, then I need to
specify which one I want to use. I achieved this by specifying
the types inside the foreach... concisely enough for me :)
So... I'm looking how to do the same with ´each´, as defining the
type of the lambda didn't help.
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