Why pow() won't go beyond 2^31?

[Daniel Kozak]

On Thu, Nov 29, 2018 at 8:10 AM Murilo via Digitalmars-d-learn <
digitalmars-d-learn at puremagic.com> wrote:

> I am using the function pow() from std.math but if I try pow(2,
> 32) it returns 0, it doesn't compute beyond the maximum value of
> an int(2^31) and I am working with long. What should I do?
>

if you look at doc: https://dlang.org/phobos/std_math.html#.pow.2

you will see that return type is infered from pow arguments, so if both
arguments are int for example the return value would be int too
https://run.dlang.io/is/FMVJhY

so if you want to have long as output one of your args should be (u)long or
you can enforce that by
pow!long(2,32);

https://run.dlang.io/is/WlDfsE
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