signed nibble

[Patrick Schluter]

On Monday, 7 January 2019 at 18:47:04 UTC, Adam D. Ruppe wrote:
> On Monday, 7 January 2019 at 18:42:13 UTC, Patrick Schluter 
> wrote:
>> byte b = nibble | ((nibble & 0x40)?0xF0:0);
>
> don't you mean & 0x80 ?

He asked for signed nybble. So mine is wrong and yours also :-)

It's obviously 0x08 for the highest bit of the low nybble.

byte b = nibble | ((nibble & 0x08)?0xF0:0);