Implement Interface Using Super

[Meta]

On Wednesday, 30 January 2019 at 01:02:37 UTC, Jonathan M Davis 
wrote:
> Yeah. It would be like trying to do something like
>
> alias x = this.x;
>
> As it stands, I believe that super is always either used as a 
> function call to the constructor or to mean the this pointer 
> for the base class. I don't think that it ever means the type 
> of the base class - just like this never means the type of the 
> current class or struct. And their usage is pretty much 
> identical. They're both either used for calling a constructor 
> or for accessing the pointer/reference of the object. It's just 
> that one of them is for the current class or struct, whereas 
> the other is for a base class of the current class. The only 
> difference in syntax that I can think of between them at the 
> moment is that this is also used to name constructors when 
> they're declared, whereas super is not used in that sort of way 
> (since any constructor that would be referenced by super would 
> be declared with this, not super).
>
> - Jonathan M Davis

Current, you *can* use `super` to mean the type of the base 
class, but it's been deprecated in a recent release (IIRC):

class Super
{
}

class Sub
{
     super test()
     {
     	return new Super();
     }
}

void main()
{
     (new Sub()).test();
}

 From DPaste:

Up to      2.080.1: Success and no output
Since      2.081.2: Success with output: onlineapp.d(7): 
Deprecation: Using `super` as a type is deprecated. Use 
`typeof(super)` instead