Operator Overloading with multiple return types

[Ali Çehreli]

On 03/15/2019 03:48 PM, H. S. Teoh wrote:
> On Fri, Mar 15, 2019 at 10:30:41PM +0000, eXodiquas via Digitalmars-d-learn wrote:
>> On Friday, 15 March 2019 at 21:46:50 UTC, Ali Çehreli wrote:
> [...]
>>> Or use template constraints:
>>>
>>> struct Vector {
>>>    Vector opBinary(string op)(Vector rhs)
>>>      if (op == "+") {
>>>        return Vector();
>>>      }
>>>
>>>    double opBinary(string op)(Vector rhs)
>>>      if (op == "/") {
>>>        return 0.5;
>>>      }
>>> }
>>>
>>> Ali
>>
>> Thanks for the quick and simple answers, but I don't get this one. If
>> I do it that way the compiler doesn't know which function to call, or
>> am I doing something wrong?
>>
>> Vector2 opBinary(string op)(Vector2 rhs) {
>>          if (op == "+") {
>>              return Vector2(this.x + rhs.x, this.y + rhs.y);
>>          } else if (op == "-") {
>>              return Vector2(this.x - rhs.x, this.y - rhs.y);
>>          }
>>      }
>>
>>      float opBinary(string op)(Vector2 rhs) {
>>          if (op == "*") {
>>              return this.x * rhs.x + this.y * rhs.y;
>>          }
>>      }
>>
>> This gives me the error:
>> overloads (Vector2 rhs) and (Vector2 rhs) both match argument list for
>> opBinary
> [...]
> 
> Ali's example was unfortunately deceptively formatted.

My editor did that. :)

On my work computer, I've been experimenting with pulling the 'if', 
'in', etc to the same level as the function signature:

   int foo(T)(T t)
   if (isBlah!T)
   in (!t.empty) {
     // ...
   }

Ali