What does the [] operator do here?
WebFreak001
d.forum at webfreak.org
Thu Apr 2 07:07:02 UTC 2020
On Wednesday, 1 April 2020 at 19:35:30 UTC, Net wrote:
> from the below code, the expression "case [c]":
>
> void main()
> {
> import std.stdio, std.string, std.algorithm, std.conv;
>
> // Reduce the RPN expression using a stack
> readln.split.fold!((stack, op)
> {
> switch (op)
> {
> // Generate operator switch cases statically
> static foreach (c; "+-*/")
> case [c]:
> return stack[0 .. $ - 2] ~
> mixin("stack[$ - 2] " ~ c ~
> " stack[$ - 1]");
> default: return stack ~ op.to!real;
> }
> })((real[]).init).writeln;
> }
the `static foreach (c; "+-*/")` operates on the characters, so c
will be a char.
You use c in the case for the `switch (op)` where op is some char
array (string), so if you want to check it in the switch, you
will have to make c an array.
Here the example uses [c] but you could also `static foreach (c;
["+", "-", "*", "/"])` but I think [c] is a more elegant solution
because it's done at compile time anyway. (case values are
evaluated at compile time like if you would write enum x = [c];)
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