how to skip the next (n) item & continue from (n+1) with a range ? e.g. in File(fn).byLine();
mw
mingwu at gmail.com
Mon Jun 22 20:46:30 UTC 2020
On Monday, 22 June 2020 at 20:00:50 UTC, Steven Schveighoffer
wrote:
> I wouldn't recommend it, instead do a while loop:
>
> auto range = File(fn).byLine;
>
> while(!range.empty)
> {
> auto line = range.front;
> if(someCond(line)) {
> range.popFrontN(n);
> } else {
> regularProcess(line);
> range.popFront;
> }
> }
Thanks.
so `front` is peek, and `popFront` is the pop action whose return
type is `void`, why we need two *separate* calls instead of just
let `popFront` return T (or do we have another function for
this)? i.e if the user forget `popFront`, it will prone to
infinite loop bug?
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