how to skip the next (n) item & continue from (n+1) with a range ? e.g. in File(fn).byLine();
mw
mingwu at gmail.com
Mon Jun 22 20:51:49 UTC 2020
On Monday, 22 June 2020 at 20:49:55 UTC, mw wrote:
> On Monday, 22 June 2020 at 20:46:30 UTC, mw wrote:
>> On Monday, 22 June 2020 at 20:00:50 UTC, Steven Schveighoffer
>> wrote:
>>> I wouldn't recommend it, instead do a while loop:
>>>
>>> auto range = File(fn).byLine;
>>>
>>> while(!range.empty)
>>> {
>>> auto line = range.front;
>>> if(someCond(line)) {
>>> range.popFrontN(n);
>
> I'm asking this, because here it need to be
either
> range.popFrontN(n+1);
>
> i.e. bug-prone
or
> can be fixed by:
> auto line = range.front;
> range.popFront; // pop immediately
of course.
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