how to skip the next (n) item & continue from (n+1) with a range ? e.g. in File(fn).byLine();

[Ali Çehreli]

On 6/22/20 1:46 PM, mw wrote:

 > so `front` is peek, and `popFront` is the pop action whose return type
 > is `void`, why we need two *separate* calls instead of just let
 > `popFront` return T

Others have other explanations for this but my understanding is about 
exception safety: If it changed internal state and returned the front 
object, you would no be able to make a function like popFront() strongly 
exception safe. (There are ample documentation for this topic in C++ 
circles.)

Another reason is cohesion: We want functions to have as little 
responsibility as possible (ideally single).

 > (or do we have another function for this)?

There are many useful functions in std.range:

   https://dlang.org/phobos/std_range.html

The "take" and "drop" functions may be useful.

Ali