Passing a derived class where base class is defined as ref parameter
Tejas
notrealemail at gmail.com
Tue Dec 14 05:38:17 UTC 2021
On Monday, 13 December 2021 at 22:30:59 UTC, Adam D Ruppe wrote:
> On Monday, 13 December 2021 at 22:06:45 UTC, chopchop wrote:
>> If I remove the ref, it works as expected, that is to say I
>> can give a derived class as parameter.
>
> Why are you using the ref to begin with?
>
>> What the logic here?
>
> Consider this:
>
>
> class C : A {}
>
> void incr(ref A a) {
> a = new C;
> }
>
> B b = new B;
> incr(b);
> // oops b now got rebound to a C instead of to a B, which
> breaks everything
But `B` is not a child of `A`, why should it be accepted in a
function that accepts `A` as a parameter? It's not implicitly
convertible to `A`
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